Base | Representation |
---|---|
bin | 1100001100000010110001… |
… | …1000011010111111000011 |
3 | 1202110010102200211120212011 |
4 | 3003000230120122333003 |
5 | 3224030313344004021 |
6 | 44300204242313351 |
7 | 2552123220214615 |
oct | 303005430327703 |
9 | 52403380746764 |
10 | 13401042563011 |
11 | 42a7394187114 |
12 | 1605266058857 |
13 | 7629362b6c3c |
14 | 344884854db5 |
15 | 1838d286cde1 |
hex | c302c61afc3 |
13401042563011 has 32 divisors (see below), whose sum is σ = 13929799514112. Its totient is φ = 12878660551680.
The previous prime is 13401042563003. The next prime is 13401042563021. The reversal of 13401042563011 is 11036524010431.
It is a cyclic number.
It is not a de Polignac number, because 13401042563011 - 23 = 13401042563003 is a prime.
It is a super-2 number, since 2×134010425630112 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (31).
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13401042563021) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6644045875 + ... + 6644047891.
It is an arithmetic number, because the mean of its divisors is an integer number (435306234816).
Almost surely, 213401042563011 is an apocalyptic number.
13401042563011 is a deficient number, since it is larger than the sum of its proper divisors (528756951101).
13401042563011 is a wasteful number, since it uses less digits than its factorization.
13401042563011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4219.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 13401042563011 its reverse (11036524010431), we get a palindrome (24437566573442).
The spelling of 13401042563011 in words is "thirteen trillion, four hundred one billion, forty-two million, five hundred sixty-three thousand, eleven".
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