13401042563021 has 2 divisors, whose sum is σ = 13401042563022. Its totient is φ = 13401042563020.

The previous prime is 13401042563003. The next prime is 13401042563057. The reversal of 13401042563021 is 12036524010431.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 8029935033796 + 5371107529225 = 2833714^2 + 2317565^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13401042563021 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13401042563621) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700521281510 + 6700521281511.

It is an arithmetic number, because the mean of its divisors is an integer number (6700521281511).

Almost surely, 2^{13401042563021} is an apocalyptic number.

It is an amenable number.

13401042563021 is a deficient number, since it is larger than the sum of its proper divisors (1).

13401042563021 is an equidigital number, since it uses as much as digits as its factorization.

13401042563021 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 13401042563021 its reverse (12036524010431), we get a palindrome (25437566573452).

The spelling of 13401042563021 in words is "thirteen trillion, four hundred one billion, forty-two million, five hundred sixty-three thousand, twenty-one".