13401042563003 has 2 divisors, whose sum is σ = 13401042563004. Its totient is φ = 13401042563002.

The previous prime is 13401042562997. The next prime is 13401042563021. The reversal of 13401042563003 is 30036524010431.

13401042563003 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13401042563003 is a prime.

It is not a weakly prime, because it can be changed into another prime (13401042563203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6700521281501 + 6700521281502.

It is an arithmetic number, because the mean of its divisors is an integer number (6700521281502).

Almost surely, 2^{13401042563003} is an apocalyptic number.

13401042563003 is a deficient number, since it is larger than the sum of its proper divisors (1).

13401042563003 is an equidigital number, since it uses as much as digits as its factorization.

13401042563003 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 25920, while the sum is 32.

Adding to 13401042563003 its reverse (30036524010431), we get a palindrome (43437566573434).

The spelling of 13401042563003 in words is "thirteen trillion, four hundred one billion, forty-two million, five hundred sixty-three thousand, three".