14032000117 has 4 divisors (see below), whose sum is σ = 14515862220. Its totient is φ = 13548138016.

The previous prime is 14032000111. The next prime is 14032000121. The reversal of 14032000117 is 71100023041.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 71100023041 = 2837 ⋅25061693.

It can be written as a sum of positive squares in 2 ways, for example, as 8589397041 + 5442603076 = 92679^2 + 73774^2 .

It is a cyclic number.

It is not a de Polignac number, because 14032000117 - 2³ = 14032000109 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 14032000094 and 14032000103.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14032000111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 241931008 + ... + 241931065.

It is an arithmetic number, because the mean of its divisors is an integer number (3628965555).

Almost surely, 2^14032000117 is an apocalyptic number.

It is an amenable number.

14032000117 is a deficient number, since it is larger than the sum of its proper divisors (483862103).

14032000117 is an equidigital number, since it uses as much as digits as its factorization.

14032000117 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 483862102.

The product of its (nonzero) digits is 168, while the sum is 19.

Adding to 14032000117 its reverse (71100023041), we get a palindrome (85132023158).

The spelling of 14032000117 in words is "fourteen billion, thirty-two million, one hundred seventeen", and thus it is an aban number.