14032000121 has 2 divisors, whose sum is σ = 14032000122. Its totient is φ = 14032000120.

The previous prime is 14032000111. The next prime is 14032000123. The reversal of 14032000121 is 12100023041.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12482475625 + 1549524496 = 111725^2 + 39364^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14032000121 is a prime.

It is a Sophie Germain prime.

Together with 14032000123, it forms a pair of twin primes.

It is a Chen prime.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 14032000096 and 14032000105.

It is not a weakly prime, because it can be changed into another prime (14032000123) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7016000060 + 7016000061.

It is an arithmetic number, because the mean of its divisors is an integer number (7016000061).

Almost surely, 2^14032000121 is an apocalyptic number.

It is an amenable number.

14032000121 is a deficient number, since it is larger than the sum of its proper divisors (1).

14032000121 is an equidigital number, since it uses as much as digits as its factorization.

14032000121 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 48, while the sum is 14.

Adding to 14032000121 its reverse (12100023041), we get a palindrome (26132023162).

The spelling of 14032000121 in words is "fourteen billion, thirty-two million, one hundred twenty-one", and thus it is an aban number.