14032000111 has 2 divisors, whose sum is σ = 14032000112. Its totient is φ = 14032000110.

The previous prime is 14032000109. The next prime is 14032000121. The reversal of 14032000111 is 11100023041.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 14032000111 - 2¹ = 14032000109 is a prime.

Together with 14032000109, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 14032000091 and 14032000100.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14032000121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7016000055 + 7016000056.

It is an arithmetic number, because the mean of its divisors is an integer number (7016000056).

Almost surely, 2^14032000111 is an apocalyptic number.

14032000111 is a deficient number, since it is larger than the sum of its proper divisors (1).

14032000111 is an equidigital number, since it uses as much as digits as its factorization.

14032000111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 14032000111 its reverse (11100023041), we get a palindrome (25132023152).

The spelling of 14032000111 in words is "fourteen billion, thirty-two million, one hundred eleven", and thus it is an aban number.