14032000113 has 16 divisors (see below), whose sum is σ = 18769470720. Its totient is φ = 9324627984.

The previous prime is 14032000111. The next prime is 14032000121. The reversal of 14032000113 is 31100023041.

14032000113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 14032000113 - 2¹ = 14032000111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 14032000092 and 14032000101.

It is not an unprimeable number, because it can be changed into a prime (14032000111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3503370 + ... + 3507372.

It is an arithmetic number, because the mean of its divisors is an integer number (1173091920).

Almost surely, 2^14032000113 is an apocalyptic number.

It is an amenable number.

14032000113 is a deficient number, since it is larger than the sum of its proper divisors (4737470607).

14032000113 is a wasteful number, since it uses less digits than its factorization.

14032000113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7468.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 14032000113 its reverse (31100023041), we get a palindrome (45132023154).

The spelling of 14032000113 in words is "fourteen billion, thirty-two million, one hundred thirteen", and thus it is an aban number.