Base | Representation |
---|---|
bin | 1100001100000010110001… |
… | …1000011010111110111010 |
3 | 1202110010102200211120211211 |
4 | 3003000230120122332322 |
5 | 3224030313344004002 |
6 | 44300204242313334 |
7 | 2552123220214603 |
oct | 303005430327672 |
9 | 52403380746754 |
10 | 13401042563002 |
11 | 42a7394187106 |
12 | 160526605884a |
13 | 7629362b6c33 |
14 | 344884854daa |
15 | 1838d286cdd7 |
hex | c302c61afba |
13401042563002 has 4 divisors (see below), whose sum is σ = 20101563844506. Its totient is φ = 6700521281500.
The previous prime is 13401042562997. The next prime is 13401042563003. The reversal of 13401042563002 is 20036524010431.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 12229645462281 + 1171397100721 = 3497091^2 + 1082311^2 .
It is not an unprimeable number, because it can be changed into a prime (13401042563003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3350260640749 + ... + 3350260640752.
Almost surely, 213401042563002 is an apocalyptic number.
13401042563002 is a deficient number, since it is larger than the sum of its proper divisors (6700521281504).
13401042563002 is an equidigital number, since it uses as much as digits as its factorization.
13401042563002 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6700521281503.
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 13401042563002 its reverse (20036524010431), we get a palindrome (33437566573433).
The spelling of 13401042563002 in words is "thirteen trillion, four hundred one billion, forty-two million, five hundred sixty-three thousand, two".
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