Base | Representation |
---|---|
bin | 1011110100110101011000… |
… | …0101001010101100101111 |
3 | 1201001000020100112212001120 |
4 | 2331031112011022230233 |
5 | 3201012212402400421 |
6 | 43353102344112023 |
7 | 2511246240104601 |
oct | 275152605125457 |
9 | 51030210485046 |
10 | 13002310200111 |
11 | 4163281158291 |
12 | 155bb27465613 |
13 | 73416049222b |
14 | 32d45ab8b171 |
15 | 1783473c08c6 |
hex | bd35614ab2f |
13002310200111 has 4 divisors (see below), whose sum is σ = 17336413600152. Its totient is φ = 8668206800072.
The previous prime is 13002310200049. The next prime is 13002310200149. The reversal of 13002310200111 is 11100201320031.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13002310200111 - 211 = 13002310198063 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13002310200151) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2167051700016 + ... + 2167051700021.
It is an arithmetic number, because the mean of its divisors is an integer number (4334103400038).
Almost surely, 213002310200111 is an apocalyptic number.
13002310200111 is a deficient number, since it is larger than the sum of its proper divisors (4334103400041).
13002310200111 is an equidigital number, since it uses as much as digits as its factorization.
13002310200111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4334103400040.
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 13002310200111 its reverse (11100201320031), we get a palindrome (24102511520142).
The spelling of 13002310200111 in words is "thirteen trillion, two billion, three hundred ten million, two hundred thousand, one hundred eleven".
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