13002310200149 has 2 divisors, whose sum is σ = 13002310200150. Its totient is φ = 13002310200148.

The previous prime is 13002310200049. The next prime is 13002310200151. The reversal of 13002310200149 is 94100201320031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6791199516049 + 6211110684100 = 2605993^2 + 2492210^2 .

It is an emirp because it is prime and its reverse (94100201320031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13002310200149 - 2¹⁶ = 13002310134613 is a prime.

Together with 13002310200151, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13002310200169) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501155100074 + 6501155100075.

It is an arithmetic number, because the mean of its divisors is an integer number (6501155100075).

Almost surely, 2^{13002310200149} is an apocalyptic number.

It is an amenable number.

13002310200149 is a deficient number, since it is larger than the sum of its proper divisors (1).

13002310200149 is an equidigital number, since it uses as much as digits as its factorization.

13002310200149 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 26.

The spelling of 13002310200149 in words is "thirteen trillion, two billion, three hundred ten million, two hundred thousand, one hundred forty-nine".