13002310200049 has 2 divisors, whose sum is σ = 13002310200050. Its totient is φ = 13002310200048.

The previous prime is 13002310200017. The next prime is 13002310200149. The reversal of 13002310200049 is 94000201320031.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9855003575824 + 3147306624225 = 3139268^2 + 1774065^2 .

It is a cyclic number.

It is not a de Polignac number, because 13002310200049 - 2⁵ = 13002310200017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13002310199996 and 13002310200032.

It is not a weakly prime, because it can be changed into another prime (13002310200149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6501155100024 + 6501155100025.

It is an arithmetic number, because the mean of its divisors is an integer number (6501155100025).

Almost surely, 2^{13002310200049} is an apocalyptic number.

It is an amenable number.

13002310200049 is a deficient number, since it is larger than the sum of its proper divisors (1).

13002310200049 is an equidigital number, since it uses as much as digits as its factorization.

13002310200049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1296, while the sum is 25.

The spelling of 13002310200049 in words is "thirteen trillion, two billion, three hundred ten million, two hundred thousand, forty-nine".