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12003103130234 = 28967433163653
BaseRepresentation
bin1010111010101011000010…
…1100101100001001111010
31120111111002220011110012212
42232222300230230021322
53033124323400131414
641310052140535122
72346124041125306
oct256526054541172
946444086143185
1012003103130234
11390853a884547
12141a346b514a2
13690b70572618
142d6d4bb8cd06
1515c36558683e
hexaeab0b2c27a

12003103130234 has 8 divisors (see below), whose sum is σ = 18206954186580. Its totient is φ = 5934118401376.

The previous prime is 12003103130147. The next prime is 12003103130267. The reversal of 12003103130234 is 43203130130021.

12003103130234 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 12001824853225 + 1278277009 = 3464365^2 + 35753^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 33716581649 + ... + 33716582004.

Almost surely, 212003103130234 is an apocalyptic number.

12003103130234 is a deficient number, since it is larger than the sum of its proper divisors (6203851056346).

12003103130234 is an equidigital number, since it uses as much as digits as its factorization.

12003103130234 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 67433163744.

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 12003103130234 its reverse (43203130130021), we get a palindrome (55206233260255).

The spelling of 12003103130234 in words is "twelve trillion, three billion, one hundred three million, one hundred thirty thousand, two hundred thirty-four".

Divisors: 1 2 89 178 67433163653 134866327306 6001551565117 12003103130234