12003103130267 has 2 divisors, whose sum is σ = 12003103130268. Its totient is φ = 12003103130266.

The previous prime is 12003103130147. The next prime is 12003103130269. The reversal of 12003103130267 is 76203130130021.

12003103130267 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12003103130267 is a prime.

Together with 12003103130269, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (12003103130269) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6001551565133 + 6001551565134.

It is an arithmetic number, because the mean of its divisors is an integer number (6001551565134).

Almost surely, 2^{12003103130267} is an apocalyptic number.

12003103130267 is a deficient number, since it is larger than the sum of its proper divisors (1).

12003103130267 is an equidigital number, since it uses as much as digits as its factorization.

12003103130267 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4536, while the sum is 29.

Adding to 12003103130267 its reverse (76203130130021), we get a palindrome (88206233260288).

The spelling of 12003103130267 in words is "twelve trillion, three billion, one hundred three million, one hundred thirty thousand, two hundred sixty-seven".