Base | Representation |
---|---|
bin | 110011011010010011… |
… | …1000001100100011000 |
3 | 101112222021012010020102 |
4 | 1212310213001210120 |
5 | 3302102000430240 |
6 | 122415151314532 |
7 | 10655631106442 |
oct | 1466447014430 |
9 | 345867163212 |
10 | 110404311320 |
11 | 429053a01a6 |
12 | 1949221ba48 |
13 | a5461ba984 |
14 | 54b4b8b492 |
15 | 2d1285d815 |
hex | 19b49c1918 |
110404311320 has 64 divisors (see below), whose sum is σ = 252180345600. Its totient is φ = 43495260160.
The previous prime is 110404311299. The next prime is 110404311337. The reversal of 110404311320 is 23113404011.
110404311320 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×1104043113202 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 110404311292 and 110404311301.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 854585 + ... + 975255.
It is an arithmetic number, because the mean of its divisors is an integer number (3940317900).
Almost surely, 2110404311320 is an apocalyptic number.
110404311320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 110404311320, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (126090172800).
110404311320 is an abundant number, since it is smaller than the sum of its proper divisors (141776034280).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
110404311320 is a wasteful number, since it uses less digits than its factorization.
110404311320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 121028 (or 121024 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 20.
Adding to 110404311320 its reverse (23113404011), we get a palindrome (133517715331).
The spelling of 110404311320 in words is "one hundred ten billion, four hundred four million, three hundred eleven thousand, three hundred twenty".
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