1013330001113 has 8 divisors (see below), whose sum is σ = 1013803116288. Its totient is φ = 1012857001344.

The previous prime is 1013330001067. The next prime is 1013330001137. The reversal of 1013330001113 is 3111000333101.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1013330001113 - 2⁶ = 1013330001049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1013330001091 and 1013330001100.

It is not an unprimeable number, because it can be changed into a prime (1013330001163) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 20932745 + ... + 20981097.

It is an arithmetic number, because the mean of its divisors is an integer number (126725389536).

Almost surely, 2^{1013330001113} is an apocalyptic number.

It is an amenable number.

1013330001113 is a deficient number, since it is larger than the sum of its proper divisors (473115175).

1013330001113 is an equidigital number, since it uses as much as digits as its factorization.

1013330001113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 57703.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 1013330001113 its reverse (3111000333101), we get a palindrome (4124330334214).

The spelling of 1013330001113 in words is "one trillion, thirteen billion, three hundred thirty million, one thousand, one hundred thirteen".