Base | Representation |
---|---|
bin | 1010101000000001… |
… | …00110001111000101 |
3 | 112201112212001111102 |
4 | 11110000212033011 |
5 | 43140312110203 |
6 | 2342013145445 |
7 | 261234454046 |
oct | 52400461705 |
9 | 15645761442 |
10 | 5704410053 |
11 | 2467a99781 |
12 | 113248b285 |
13 | 6cba83384 |
14 | 3c18668cd |
15 | 235bea888 |
hex | 1540263c5 |
5704410053 has 2 divisors, whose sum is σ = 5704410054. Its totient is φ = 5704410052.
The previous prime is 5704410031. The next prime is 5704410077. The reversal of 5704410053 is 3500144075.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 5657597089 + 46812964 = 75217^2 + 6842^2 .
It is a cyclic number.
It is not a de Polignac number, because 5704410053 - 28 = 5704409797 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5704409998 and 5704410025.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5704410253) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2852205026 + 2852205027.
It is an arithmetic number, because the mean of its divisors is an integer number (2852205027).
Almost surely, 25704410053 is an apocalyptic number.
It is an amenable number.
5704410053 is a deficient number, since it is larger than the sum of its proper divisors (1).
5704410053 is an equidigital number, since it uses as much as digits as its factorization.
5704410053 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 8400, while the sum is 29.
The square root of 5704410053 is about 75527.5449951870. The cubic root of 5704410053 is about 1786.7765559770.
The spelling of 5704410053 in words is "five billion, seven hundred four million, four hundred ten thousand, fifty-three".
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