Base | Representation |
---|---|
bin | 1010101000000001… |
… | …00110001110101111 |
3 | 112201112212001110121 |
4 | 11110000212032233 |
5 | 43140312110111 |
6 | 2342013145411 |
7 | 261234454015 |
oct | 52400461657 |
9 | 15645761417 |
10 | 5704410031 |
11 | 2467a99761 |
12 | 113248b267 |
13 | 6cba83368 |
14 | 3c18668b5 |
15 | 235bea871 |
hex | 1540263af |
5704410031 has 2 divisors, whose sum is σ = 5704410032. Its totient is φ = 5704410030.
The previous prime is 5704410017. The next prime is 5704410053. The reversal of 5704410031 is 1300144075.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5704410031 - 25 = 5704409999 is a prime.
It is a super-2 number, since 2×57044100312 = 65080587603546841922, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5704409978 and 5704410005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (5704410431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2852205015 + 2852205016.
It is an arithmetic number, because the mean of its divisors is an integer number (2852205016).
Almost surely, 25704410031 is an apocalyptic number.
5704410031 is a deficient number, since it is larger than the sum of its proper divisors (1).
5704410031 is an equidigital number, since it uses as much as digits as its factorization.
5704410031 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1680, while the sum is 25.
The square root of 5704410031 is about 75527.5448495448. The cubic root of 5704410031 is about 1786.7765536800.
The spelling of 5704410031 in words is "five billion, seven hundred four million, four hundred ten thousand, thirty-one".
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