Base | Representation |
---|---|
bin | 110001011111000011… |
… | …011001110001000100 |
3 | 12002011000121212222222 |
4 | 301133003121301010 |
5 | 1332304342210134 |
6 | 40224245111512 |
7 | 3560501252540 |
oct | 613703316104 |
9 | 162130555888 |
10 | 53134335044 |
11 | 20596a4639a |
12 | a36a6b8598 |
13 | 501a229c4b |
14 | 2800b04a20 |
15 | 15aeb21a2e |
hex | c5f0d9c44 |
53134335044 has 24 divisors (see below), whose sum is σ = 106288932288. Its totient is φ = 22767516000.
The previous prime is 53134335043. The next prime is 53134335139. The reversal of 53134335044 is 44053343135.
It is a junction number, because it is equal to n+sod(n) for n = 53134334995 and 53134335013.
It is not an unprimeable number, because it can be changed into a prime (53134335043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 29207 + ... + 327294.
It is an arithmetic number, because the mean of its divisors is an integer number (4428705512).
Almost surely, 253134335044 is an apocalyptic number.
It is an amenable number.
53134335044 is an abundant number, since it is smaller than the sum of its proper divisors (53154597244).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
53134335044 is a wasteful number, since it uses less digits than its factorization.
53134335044 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 361835 (or 361833 counting only the distinct ones).
The product of its (nonzero) digits is 129600, while the sum is 35.
Adding to 53134335044 its reverse (44053343135), we get a palindrome (97187678179).
The spelling of 53134335044 in words is "fifty-three billion, one hundred thirty-four million, three hundred thirty-five thousand, forty-four".
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