Base | Representation |
---|---|
bin | 110001011111000011… |
… | …011001110001000011 |
3 | 12002011000121212222221 |
4 | 301133003121301003 |
5 | 1332304342210133 |
6 | 40224245111511 |
7 | 3560501252536 |
oct | 613703316103 |
9 | 162130555887 |
10 | 53134335043 |
11 | 20596a46399 |
12 | a36a6b8597 |
13 | 501a229c4a |
14 | 2800b04a1d |
15 | 15aeb21a2d |
hex | c5f0d9c43 |
53134335043 has 2 divisors, whose sum is σ = 53134335044. Its totient is φ = 53134335042.
The previous prime is 53134335029. The next prime is 53134335139. The reversal of 53134335043 is 34053343135.
53134335043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 53134335043 - 213 = 53134326851 is a prime.
It is not a weakly prime, because it can be changed into another prime (53134339043) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 26567167521 + 26567167522.
It is an arithmetic number, because the mean of its divisors is an integer number (26567167522).
Almost surely, 253134335043 is an apocalyptic number.
53134335043 is a deficient number, since it is larger than the sum of its proper divisors (1).
53134335043 is an equidigital number, since it uses as much as digits as its factorization.
53134335043 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 97200, while the sum is 34.
Adding to 53134335043 its reverse (34053343135), we get a palindrome (87187678178).
The spelling of 53134335043 in words is "fifty-three billion, one hundred thirty-four million, three hundred thirty-five thousand, forty-three".
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