Base | Representation |
---|---|
bin | 110001011111000011… |
… | …011001110000111011 |
3 | 12002011000121212222122 |
4 | 301133003121300323 |
5 | 1332304342210120 |
6 | 40224245111455 |
7 | 3560501252525 |
oct | 613703316073 |
9 | 162130555878 |
10 | 53134335035 |
11 | 20596a46391 |
12 | a36a6b858b |
13 | 501a229c42 |
14 | 2800b04a15 |
15 | 15aeb21a25 |
hex | c5f0d9c3b |
53134335035 has 8 divisors (see below), whose sum is σ = 64167325296. Its totient is φ = 42236719200.
The previous prime is 53134335029. The next prime is 53134335043. The reversal of 53134335035 is 53053343135.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 53134335035 - 212 = 53134330939 is a prime.
It is a super-2 number, since 2×531343350352 (a number of 22 digits) contains 22 as substring.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 53134334986 and 53134335004.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 33842741 + ... + 33844310.
It is an arithmetic number, because the mean of its divisors is an integer number (8020915662).
Almost surely, 253134335035 is an apocalyptic number.
53134335035 is a deficient number, since it is larger than the sum of its proper divisors (11032990261).
53134335035 is a wasteful number, since it uses less digits than its factorization.
53134335035 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67687213.
The product of its (nonzero) digits is 121500, while the sum is 35.
The spelling of 53134335035 in words is "fifty-three billion, one hundred thirty-four million, three hundred thirty-five thousand, thirty-five".
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