Base | Representation |
---|---|
bin | 100110100110100101110… |
… | …1010011011101100100010 |
3 | 200210012120011220212111012 |
4 | 1031031023222123230202 |
5 | 1143411233312302000 |
6 | 15141200551420522 |
7 | 1055212401060113 |
oct | 115151352335442 |
9 | 20705504825435 |
10 | 5305554025250 |
11 | 1766088a28176 |
12 | 718303384742 |
13 | 2c640877113b |
14 | 144b0c3a620a |
15 | 930227c2735 |
hex | 4d34ba9bb22 |
5305554025250 has 64 divisors (see below), whose sum is σ = 10624647852000. Its totient is φ = 1976793292800.
The previous prime is 5305554025231. The next prime is 5305554025253. The reversal of 5305554025250 is 525204555035.
It can be written as a sum of positive squares in 16 ways, for example, as 734591268889 + 4570962756361 = 857083^2 + 2137981^2 .
It is a junction number, because it is equal to n+sod(n) for n = 5305554025198 and 5305554025207.
It is not an unprimeable number, because it can be changed into a prime (5305554025253) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 6022625 + ... + 6847124.
Almost surely, 25305554025250 is an apocalyptic number.
5305554025250 is a gapful number since it is divisible by the number (50) formed by its first and last digit.
5305554025250 is an abundant number, since it is smaller than the sum of its proper divisors (5319093826750).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5305554025250 is a wasteful number, since it uses less digits than its factorization.
5305554025250 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 12869880 (or 12869870 counting only the distinct ones).
The product of its (nonzero) digits is 750000, while the sum is 41.
The spelling of 5305554025250 in words is "five trillion, three hundred five billion, five hundred fifty-four million, twenty-five thousand, two hundred fifty".
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