Base | Representation |
---|---|
bin | 100101111011100011101… |
… | …0111011001101000000111 |
3 | 200110101000200212121000121 |
4 | 1023313013113121220013 |
5 | 1140403002333132221 |
6 | 15030514501122411 |
7 | 1045431320656021 |
oct | 113670727315007 |
9 | 20411020777017 |
10 | 5213140130311 |
11 | 172a975774093 |
12 | 7024120b9407 |
13 | 2ba79b809879 |
14 | 140462a6d011 |
15 | 90914577a41 |
hex | 4bdc75d9a07 |
5213140130311 has 8 divisors (see below), whose sum is σ = 5637237888960. Its totient is φ = 4802091533568.
The previous prime is 5213140130309. The next prime is 5213140130321. The reversal of 5213140130311 is 1130310413125.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 5213140130311 - 21 = 5213140130309 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5213140130321) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3262289646 + ... + 3262291243.
It is an arithmetic number, because the mean of its divisors is an integer number (704654736120).
Almost surely, 25213140130311 is an apocalyptic number.
5213140130311 is a deficient number, since it is larger than the sum of its proper divisors (424097758649).
5213140130311 is a wasteful number, since it uses less digits than its factorization.
5213140130311 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6524580953.
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 5213140130311 its reverse (1130310413125), we get a palindrome (6343450543436).
The spelling of 5213140130311 in words is "five trillion, two hundred thirteen billion, one hundred forty million, one hundred thirty thousand, three hundred eleven".
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