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5213140130321 is a prime number
BaseRepresentation
bin100101111011100011101…
…0111011001101000010001
3200110101000200212121000222
41023313013113121220101
51140403002333132241
615030514501122425
71045431320656034
oct113670727315021
920411020777028
105213140130321
11172a9757740a2
127024120b9415
132ba79b809886
14140462a6d01b
1590914577a4b
hex4bdc75d9a11

5213140130321 has 2 divisors, whose sum is σ = 5213140130322. Its totient is φ = 5213140130320.

The previous prime is 5213140130309. The next prime is 5213140130323. The reversal of 5213140130321 is 1230310413125.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 5191402756225 + 21737374096 = 2278465^2 + 147436^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5213140130321 is a prime.

Together with 5213140130323, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (5213140130323) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2606570065160 + 2606570065161.

It is an arithmetic number, because the mean of its divisors is an integer number (2606570065161).

Almost surely, 25213140130321 is an apocalyptic number.

It is an amenable number.

5213140130321 is a deficient number, since it is larger than the sum of its proper divisors (1).

5213140130321 is an equidigital number, since it uses as much as digits as its factorization.

5213140130321 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2160, while the sum is 26.

Adding to 5213140130321 its reverse (1230310413125), we get a palindrome (6443450543446).

The spelling of 5213140130321 in words is "five trillion, two hundred thirteen billion, one hundred forty million, one hundred thirty thousand, three hundred twenty-one".