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505281393137 is a prime number
BaseRepresentation
bin1110101101001010001…
…11100011000111110001
31210022012221002021121202
413112211013203013301
531234304014040022
61024042325500545
751335225656103
oct7264507430761
91708187067552
10505281393137
1118531a1a0314
1281b15871755
1338856391181
141a654813573
15d224620592
hex75a51e31f1

505281393137 has 2 divisors, whose sum is σ = 505281393138. Its totient is φ = 505281393136.

The previous prime is 505281393121. The next prime is 505281393143. The reversal of 505281393137 is 731393182505.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 451401234496 + 53880158641 = 671864^2 + 232121^2 .

It is a cyclic number.

It is not a de Polignac number, because 505281393137 - 24 = 505281393121 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 505281393091 and 505281393100.

It is not a weakly prime, because it can be changed into another prime (505281393107) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252640696568 + 252640696569.

It is an arithmetic number, because the mean of its divisors is an integer number (252640696569).

Almost surely, 2505281393137 is an apocalyptic number.

It is an amenable number.

505281393137 is a deficient number, since it is larger than the sum of its proper divisors (1).

505281393137 is an equidigital number, since it uses as much as digits as its factorization.

505281393137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 680400, while the sum is 47.

The spelling of 505281393137 in words is "five hundred five billion, two hundred eighty-one million, three hundred ninety-three thousand, one hundred thirty-seven".