Base | Representation |
---|---|
bin | 1110101101001010001… |
… | …11100011000111100001 |
3 | 1210022012221002021121011 |
4 | 13112211013203013201 |
5 | 31234304014034441 |
6 | 1024042325500521 |
7 | 51335225656051 |
oct | 7264507430741 |
9 | 1708187067534 |
10 | 505281393121 |
11 | 18531a1a02aa |
12 | 81b15871741 |
13 | 3885639116b |
14 | 1a654813561 |
15 | d224620581 |
hex | 75a51e31e1 |
505281393121 has 2 divisors, whose sum is σ = 505281393122. Its totient is φ = 505281393120.
The previous prime is 505281393107. The next prime is 505281393137. The reversal of 505281393121 is 121393182505.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 385437338896 + 119844054225 = 620836^2 + 346185^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-505281393121 is a prime.
It is a super-2 number, since 2×5052813931212 (a number of 24 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (505281393151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 252640696560 + 252640696561.
It is an arithmetic number, because the mean of its divisors is an integer number (252640696561).
Almost surely, 2505281393121 is an apocalyptic number.
It is an amenable number.
505281393121 is a deficient number, since it is larger than the sum of its proper divisors (1).
505281393121 is an equidigital number, since it uses as much as digits as its factorization.
505281393121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 40.
The spelling of 505281393121 in words is "five hundred five billion, two hundred eighty-one million, three hundred ninety-three thousand, one hundred twenty-one".
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