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4142505205303 = 34054112164483
BaseRepresentation
bin111100010010000000100…
…011010001111000110111
3112200000112022101012021221
4330102000203101320313
51020332322313032203
612451012435051211
7605200066161013
oct74220043217067
915600468335257
104142505205303
111357910214613
1256aa18740b07
132408376c021a
141046d9575543
1572b51ad4abd
hex3c4808d1e37

4142505205303 has 4 divisors (see below), whose sum is σ = 4142517710328. Its totient is φ = 4142492700280.

The previous prime is 4142505205283. The next prime is 4142505205373. The reversal of 4142505205303 is 3035025052414.

4142505205303 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 4142505205303 - 25 = 4142505205271 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (4142505205373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5741701 + ... + 6422782.

It is an arithmetic number, because the mean of its divisors is an integer number (1035629427582).

Almost surely, 24142505205303 is an apocalyptic number.

4142505205303 is a deficient number, since it is larger than the sum of its proper divisors (12505025).

4142505205303 is a wasteful number, since it uses less digits than its factorization.

4142505205303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12505024.

The product of its (nonzero) digits is 72000, while the sum is 34.

The spelling of 4142505205303 in words is "four trillion, one hundred forty-two billion, five hundred five million, two hundred five thousand, three hundred three".

Divisors: 1 340541 12164483 4142505205303