Base | Representation |
---|---|
bin | 10010001111101101000101… |
… | …10000100001110110101111 |
3 | 12021001121221120100111100221 |
4 | 21013312202300201312233 |
5 | 20224324344124030021 |
6 | 221155445051232211 |
7 | 11310502030122316 |
oct | 1107664260416657 |
9 | 167047846314327 |
10 | 40122020142511 |
11 | 1186972043415a |
12 | 45bbabb448667 |
13 | 195064b15c418 |
14 | 9c9cb7c4127d |
15 | 4989ec213241 |
hex | 247da2c21daf |
40122020142511 has 4 divisors (see below), whose sum is σ = 40264803132624. Its totient is φ = 39979237152400.
The previous prime is 40122020142509. The next prime is 40122020142553. The reversal of 40122020142511 is 11524102022104.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 40122020142511 - 21 = 40122020142509 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (40122020143511) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 71391494635 + ... + 71391495196.
It is an arithmetic number, because the mean of its divisors is an integer number (10066200783156).
Almost surely, 240122020142511 is an apocalyptic number.
40122020142511 is a deficient number, since it is larger than the sum of its proper divisors (142782990113).
40122020142511 is a wasteful number, since it uses less digits than its factorization.
40122020142511 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 142782990112.
The product of its (nonzero) digits is 1280, while the sum is 25.
Adding to 40122020142511 its reverse (11524102022104), we get a palindrome (51646122164615).
The spelling of 40122020142511 in words is "forty trillion, one hundred twenty-two billion, twenty million, one hundred forty-two thousand, five hundred eleven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.079 sec. • engine limits •