Base | Representation |
---|---|
bin | 110011100101100110000… |
… | …110101010111110111001 |
3 | 110112220102101210012120212 |
4 | 303211212012222332321 |
5 | 431040241111403103 |
6 | 11312324545200505 |
7 | 514056626455136 |
oct | 63454606527671 |
9 | 13486371705525 |
10 | 3545061044153 |
11 | 11474a75a3632 |
12 | 493081930135 |
13 | 1c93b44130c5 |
14 | c382091958d |
15 | 623363227d8 |
hex | 339661aafb9 |
3545061044153 has 2 divisors, whose sum is σ = 3545061044154. Its totient is φ = 3545061044152.
The previous prime is 3545061044141. The next prime is 3545061044177. The reversal of 3545061044153 is 3514401605453.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 3338484431104 + 206576613049 = 1827152^2 + 454507^2 .
It is a cyclic number.
It is not a de Polignac number, because 3545061044153 - 28 = 3545061043897 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 3545061044153.
It is not a weakly prime, because it can be changed into another prime (3545061044113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1772530522076 + 1772530522077.
It is an arithmetic number, because the mean of its divisors is an integer number (1772530522077).
Almost surely, 23545061044153 is an apocalyptic number.
It is an amenable number.
3545061044153 is a deficient number, since it is larger than the sum of its proper divisors (1).
3545061044153 is an equidigital number, since it uses as much as digits as its factorization.
3545061044153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432000, while the sum is 41.
The spelling of 3545061044153 in words is "three trillion, five hundred forty-five billion, sixty-one million, forty-four thousand, one hundred fifty-three".
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