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3545061044141 is a prime number
BaseRepresentation
bin110011100101100110000…
…110101010111110101101
3110112220102101210012120102
4303211212012222332231
5431040241111403031
611312324545200445
7514056626455121
oct63454606527655
913486371705512
103545061044141
1111474a75a3621
12493081930125
131c93b44130b6
14c3820919581
15623363227cb
hex339661aafad

3545061044141 has 2 divisors, whose sum is σ = 3545061044142. Its totient is φ = 3545061044140.

The previous prime is 3545061044113. The next prime is 3545061044153. The reversal of 3545061044141 is 1414401605453.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2749557596041 + 795503448100 = 1658179^2 + 891910^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-3545061044141 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 3545061044095 and 3545061044104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (3545061043141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1772530522070 + 1772530522071.

It is an arithmetic number, because the mean of its divisors is an integer number (1772530522071).

Almost surely, 23545061044141 is an apocalyptic number.

It is an amenable number.

3545061044141 is a deficient number, since it is larger than the sum of its proper divisors (1).

3545061044141 is an equidigital number, since it uses as much as digits as its factorization.

3545061044141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 115200, while the sum is 38.

Adding to 3545061044141 its reverse (1414401605453), we get a palindrome (4959462649594).

The spelling of 3545061044141 in words is "three trillion, five hundred forty-five billion, sixty-one million, forty-four thousand, one hundred forty-one".