Base | Representation |
---|---|
bin | 100101100010000001001110… |
… | …1000010111011010101110000 |
3 | 1121021220012211002012011222020 |
4 | 1023010002131002323111300 |
5 | 321232331242230430000 |
6 | 3130044031014111440 |
7 | 126352114650434412 |
oct | 11304023502732560 |
9 | 1537805732164866 |
10 | 330131001030000 |
11 | 9620a853647325 |
12 | 3103972434b580 |
13 | 112292b1c26821 |
14 | 5b745d61c69b2 |
15 | 28276e92d2ba0 |
hex | 12c409d0bb570 |
330131001030000 has 400 divisors, whose sum is σ = 1100310823028736. Its totient is φ = 85177572480000.
The previous prime is 330131001029971. The next prime is 330131001030029. The reversal of 330131001030000 is 30100131033.
It is an interprime number because it is at equal distance from previous prime (330131001029971) and next prime (330131001030029).
It is a tau number, because it is divible by the number of its divisors (400).
It is a super-2 number, since 2×3301310010300002 (a number of 30 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 4870376109 + ... + 4870443891.
Almost surely, 2330131001030000 is an apocalyptic number.
330131001030000 is a gapful number since it is divisible by the number (30) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 330131001030000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (550155411514368).
330131001030000 is an abundant number, since it is smaller than the sum of its proper divisors (770179821998736).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
330131001030000 is a wasteful number, since it uses less digits than its factorization.
330131001030000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 73082 (or 73061 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 15.
Adding to 330131001030000 its reverse (30100131033), we get a palindrome (330161101161033).
The spelling of 330131001030000 in words is "three hundred thirty trillion, one hundred thirty-one billion, one million, thirty thousand".
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