Base | Representation |
---|---|
bin | 11111000000110001110… |
… | …110010100010001100111 |
3 | 21112201211211002020110010 |
4 | 133000301312110101213 |
5 | 234404033331214343 |
6 | 4311010544301303 |
7 | 306653431654500 |
oct | 37006166242147 |
9 | 7481754066403 |
10 | 2131140101223 |
11 | 7518a2034931 |
12 | 2a5042611833 |
13 | 125c726ba4c3 |
14 | 7520d535ba7 |
15 | 3a680e98d33 |
hex | 1f031d94467 |
2131140101223 has 48 divisors (see below), whose sum is σ = 3377775859200. Its totient is φ = 1191175743744.
The previous prime is 2131140101201. The next prime is 2131140101261. The reversal of 2131140101223 is 3221010411312.
It is not a de Polignac number, because 2131140101223 - 29 = 2131140100711 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (21).
It is a self number, because there is not a number n which added to its sum of digits gives 2131140101223.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2131140101023) by changing a digit.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 11647615 + ... + 11829167.
It is an arithmetic number, because the mean of its divisors is an integer number (70370330400).
Almost surely, 22131140101223 is an apocalyptic number.
2131140101223 is a deficient number, since it is larger than the sum of its proper divisors (1246635757977).
2131140101223 is a wasteful number, since it uses less digits than its factorization.
2131140101223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 183316 (or 183309 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 21.
Adding to 2131140101223 its reverse (3221010411312), we get a palindrome (5352150512535).
The spelling of 2131140101223 in words is "two trillion, one hundred thirty-one billion, one hundred forty million, one hundred one thousand, two hundred twenty-three".
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