Base | Representation |
---|---|
bin | 11111000000110001110… |
… | …110010100001110011111 |
3 | 21112201211211002020011201 |
4 | 133000301312110032133 |
5 | 234404033331213043 |
6 | 4311010544300331 |
7 | 306653431654063 |
oct | 37006166241637 |
9 | 7481754066151 |
10 | 2131140101023 |
11 | 7518a203476a |
12 | 2a50426116a7 |
13 | 125c726ba39b |
14 | 7520d535aa3 |
15 | 3a680e98c4d |
hex | 1f031d9439f |
2131140101023 has 2 divisors, whose sum is σ = 2131140101024. Its totient is φ = 2131140101022.
The previous prime is 2131140101017. The next prime is 2131140101081. The reversal of 2131140101023 is 3201010411312.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2131140101023 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2131140131023) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1065570050511 + 1065570050512.
It is an arithmetic number, because the mean of its divisors is an integer number (1065570050512).
Almost surely, 22131140101023 is an apocalyptic number.
2131140101023 is a deficient number, since it is larger than the sum of its proper divisors (1).
2131140101023 is an equidigital number, since it uses as much as digits as its factorization.
2131140101023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 2131140101023 its reverse (3201010411312), we get a palindrome (5332150512335).
The spelling of 2131140101023 in words is "two trillion, one hundred thirty-one billion, one hundred forty million, one hundred one thousand, twenty-three".
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