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20133302211000 = 23325311375496397
BaseRepresentation
bin1001001001111101001100…
…10100111001000110111000
32122021201120110002110011200
410210332212110321012320
510114331000331223000
6110453040015054200
74145403666100356
oct444764624710670
978251513073150
1020133302211000
116462538251170
122311b76211360
13b30740363074
144d865811a7d6
1524daa7a87500
hex124fa65391b8

20133302211000 has 384 divisors, whose sum is σ = 76243394784960. Its totient is φ = 4748886144000.

The previous prime is 20133302210977. The next prime is 20133302211007. The reversal of 20133302211000 is 11220333102.

20133302211000 is a `hidden beast` number, since 2 + 0 + 13 + 330 + 221 + 100 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (20133302211007) by changing a digit.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 914802 + ... + 6411198.

Almost surely, 220133302211000 is an apocalyptic number.

20133302211000 is a gapful number since it is divisible by the number (20) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 20133302211000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (38121697392480).

20133302211000 is an abundant number, since it is smaller than the sum of its proper divisors (56110092573960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

20133302211000 is a wasteful number, since it uses less digits than its factorization.

20133302211000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5496472 (or 5496455 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 18.

Adding to 20133302211000 its reverse (11220333102), we get a palindrome (20144522544102).

It can be divided in two parts, 20133302 and 211000, that added together give a palindrome (20344302).

The spelling of 20133302211000 in words is "twenty trillion, one hundred thirty-three billion, three hundred two million, two hundred eleven thousand".