Base | Representation |
---|---|
bin | 101101110001101000000000… |
… | …110001100000100010101011 |
3 | 222101211020001221012111111011 |
4 | 231301220000301200202223 |
5 | 202341431042330323201 |
6 | 1552102105322044351 |
7 | 60256025343051205 |
oct | 5561500061404253 |
9 | 871736057174434 |
10 | 201322310011051 |
11 | 591693485a2aa9 |
12 | 1a6b57423496b7 |
13 | 88447c64cc998 |
14 | 37a00a21ab775 |
15 | 1841cc692d151 |
hex | b71a00c608ab |
201322310011051 has 2 divisors, whose sum is σ = 201322310011052. Its totient is φ = 201322310011050.
The previous prime is 201322310011021. The next prime is 201322310011061. The reversal of 201322310011051 is 150110013223102.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 201322310011051 - 223 = 201322301622443 is a prime.
It is not a weakly prime, because it can be changed into another prime (201322310011021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100661155005525 + 100661155005526.
It is an arithmetic number, because the mean of its divisors is an integer number (100661155005526).
Almost surely, 2201322310011051 is an apocalyptic number.
201322310011051 is a deficient number, since it is larger than the sum of its proper divisors (1).
201322310011051 is an equidigital number, since it uses as much as digits as its factorization.
201322310011051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 360, while the sum is 22.
Adding to 201322310011051 its reverse (150110013223102), we get a palindrome (351432323234153).
The spelling of 201322310011051 in words is "two hundred one trillion, three hundred twenty-two billion, three hundred ten million, eleven thousand, fifty-one".
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