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201322310011021 is a prime number
BaseRepresentation
bin101101110001101000000000…
…110001100000100010001101
3222101211020001221012111110001
4231301220000301200202031
5202341431042330323041
61552102105322044301
760256025343051133
oct5561500061404215
9871736057174401
10201322310011021
11591693485a2a81
121a6b5742349691
1388447c64cc974
1437a00a21ab753
151841cc692d131
hexb71a00c6088d

201322310011021 has 2 divisors, whose sum is σ = 201322310011022. Its totient is φ = 201322310011020.

The previous prime is 201322310010959. The next prime is 201322310011051. The reversal of 201322310011021 is 120110013223102.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 113121305222500 + 88201004788521 = 10635850^2 + 9391539^2 .

It is a cyclic number.

It is not a de Polignac number, because 201322310011021 - 27 = 201322310010893 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 201322310011021.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (201322310011051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 100661155005510 + 100661155005511.

It is an arithmetic number, because the mean of its divisors is an integer number (100661155005511).

Almost surely, 2201322310011021 is an apocalyptic number.

It is an amenable number.

201322310011021 is a deficient number, since it is larger than the sum of its proper divisors (1).

201322310011021 is an equidigital number, since it uses as much as digits as its factorization.

201322310011021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 201322310011021 its reverse (120110013223102), we get a palindrome (321432323234123).

The spelling of 201322310011021 in words is "two hundred one trillion, three hundred twenty-two billion, three hundred ten million, eleven thousand, twenty-one".