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1453 is a prime number
BaseRepresentation
bin10110101101
31222211
4112231
521303
610421
74144
oct2655
91884
101453
111101
12a11
1387a
1475b
1566d
hex5ad

1453 has 2 divisors, whose sum is σ = 1454. Its totient is φ = 1452.

The previous prime is 1451. The next prime is 1459. The reversal of 1453 is 3541.

1453 is nontrivially palindromic in base 2.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1444 + 9 = 38^2 + 3^2 .

It is an emirp because it is prime and its reverse (3541) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1453 - 21 = 1451 is a prime.

It is a super-2 number, since 2×14532 = 4222418, which contains 22 as substring.

Together with 1451, it forms a pair of twin primes.

It is a plaindrome in base 15 and base 16.

It is a nialpdrome in base 12.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1451) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (7) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 726 + 727.

It is an arithmetic number, because the mean of its divisors is an integer number (727).

It is an amenable number.

1453 is a deficient number, since it is larger than the sum of its proper divisors (1).

1453 is an equidigital number, since it uses as much as digits as its factorization.

1453 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 60, while the sum is 13.

The square root of 1453 is about 38.1182371051. The cubic root of 1453 is about 11.3263124528.

Adding to 1453 its reverse (3541), we get a palindrome (4994).

It can be divided in two parts, 145 and 3, that multiplied together give a triangular number (435 = T29).

The spelling of 1453 in words is "one thousand, four hundred fifty-three".