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14330118535217 is a prime number
BaseRepresentation
bin1101000010000111110110…
…0111111111100000110001
31212201221112121012002121222
43100201331213333200301
53334241040321111332
650251055432554425
73006213460532462
oct320417547774061
955657477162558
1014330118535217
114625407367201
121735333852a15
137cc42a87ac14
1437781d672d69
1519cb5c7ec712
hexd087d9ff831

14330118535217 has 2 divisors, whose sum is σ = 14330118535218. Its totient is φ = 14330118535216.

The previous prime is 14330118535169. The next prime is 14330118535219. The reversal of 14330118535217 is 71253581103341.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9802653784561 + 4527464750656 = 3130919^2 + 2127784^2 .

It is a cyclic number.

It is not a de Polignac number, because 14330118535217 - 224 = 14330101758001 is a prime.

Together with 14330118535219, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (14330118535219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7165059267608 + 7165059267609.

It is an arithmetic number, because the mean of its divisors is an integer number (7165059267609).

Almost surely, 214330118535217 is an apocalyptic number.

It is an amenable number.

14330118535217 is a deficient number, since it is larger than the sum of its proper divisors (1).

14330118535217 is an equidigital number, since it uses as much as digits as its factorization.

14330118535217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 302400, while the sum is 44.

Adding to 14330118535217 its reverse (71253581103341), we get a palindrome (85583699638558).

The spelling of 14330118535217 in words is "fourteen trillion, three hundred thirty billion, one hundred eighteen million, five hundred thirty-five thousand, two hundred seventeen".