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14330118535169 is a prime number
BaseRepresentation
bin1101000010000111110110…
…0111111111100000000001
31212201221112121012002120012
43100201331213333200001
53334241040321111134
650251055432554305
73006213460532363
oct320417547774001
955657477162505
1014330118535169
114625407367168
121735333852995
137cc42a87aba8
1437781d672d33
1519cb5c7ec6ce
hexd087d9ff801

14330118535169 has 2 divisors, whose sum is σ = 14330118535170. Its totient is φ = 14330118535168.

The previous prime is 14330118535163. The next prime is 14330118535217. The reversal of 14330118535169 is 96153581103341.

14330118535169 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13381783404544 + 948335130625 = 3658112^2 + 973825^2 .

It is a cyclic number.

It is not a de Polignac number, because 14330118535169 - 216 = 14330118469633 is a prime.

It is a super-2 number, since 2×143301185351692 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (14330118535163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7165059267584 + 7165059267585.

It is an arithmetic number, because the mean of its divisors is an integer number (7165059267585).

Almost surely, 214330118535169 is an apocalyptic number.

It is an amenable number.

14330118535169 is a deficient number, since it is larger than the sum of its proper divisors (1).

14330118535169 is an equidigital number, since it uses as much as digits as its factorization.

14330118535169 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1166400, while the sum is 50.

The spelling of 14330118535169 in words is "fourteen trillion, three hundred thirty billion, one hundred eighteen million, five hundred thirty-five thousand, one hundred sixty-nine".