1411132444231 has 8 divisors (see below), whose sum is σ = 1412752564080. Its totient is φ = 1409513101248.

The previous prime is 1411132444223. The next prime is 1411132444289. The reversal of 1411132444231 is 1324442311141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 1411132444231 - 2³ = 1411132444223 is a prime.

It is a super-2 number, since 2×1411132444231² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1411132444193 and 1411132444202.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1411132444531) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3480540 + ... + 3864766.

It is an arithmetic number, because the mean of its divisors is an integer number (176594070510).

Almost surely, 2^{1411132444231} is an apocalyptic number.

1411132444231 is a deficient number, since it is larger than the sum of its proper divisors (1620119849).

1411132444231 is a wasteful number, since it uses less digits than its factorization.

1411132444231 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 388433.

The product of its digits is 9216, while the sum is 31.

Adding to 1411132444231 its reverse (1324442311141), we get a palindrome (2735574755372).

The spelling of 1411132444231 in words is "one trillion, four hundred eleven billion, one hundred thirty-two million, four hundred forty-four thousand, two hundred thirty-one".