Base | Representation |
---|---|
bin | 10011010001011110111… |
… | …010011101100111100101 |
3 | 11200121121122212111202011 |
4 | 103101132322131213211 |
5 | 133144424212424031 |
6 | 2452235043114221 |
7 | 164454625615615 |
oct | 23213672354745 |
9 | 4617548774664 |
10 | 1324442311141 |
11 | 47076917a334 |
12 | 194829072971 |
13 | 97b81c2a841 |
14 | 48163840a45 |
15 | 246b9b866b1 |
hex | 1345ee9d9e5 |
1324442311141 has 4 divisors (see below), whose sum is σ = 1324710802252. Its totient is φ = 1324173820032.
The previous prime is 1324442311133. The next prime is 1324442311177. The reversal of 1324442311141 is 1411132444231.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 373407767041 + 951034544100 = 611071^2 + 975210^2 .
It is a cyclic number.
It is not a de Polignac number, because 1324442311141 - 23 = 1324442311133 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1324442311541) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 134238156 + ... + 134248021.
It is an arithmetic number, because the mean of its divisors is an integer number (331177700563).
Almost surely, 21324442311141 is an apocalyptic number.
It is an amenable number.
1324442311141 is a deficient number, since it is larger than the sum of its proper divisors (268491111).
1324442311141 is an equidigital number, since it uses as much as digits as its factorization.
1324442311141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 268491110.
The product of its digits is 9216, while the sum is 31.
Adding to 1324442311141 its reverse (1411132444231), we get a palindrome (2735574755372).
The spelling of 1324442311141 in words is "one trillion, three hundred twenty-four billion, four hundred forty-two million, three hundred eleven thousand, one hundred forty-one".
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