Base | Representation |
---|---|
bin | 1000001010101110111… |
… | …0010100110000011011 |
3 | 111102012010211121122222 |
4 | 2002223232110300123 |
5 | 4244333410013201 |
6 | 144243452334255 |
7 | 13065155220656 |
oct | 2025356246033 |
9 | 442163747588 |
10 | 140320001051 |
11 | 54566a8971a |
12 | 23240a7438b |
13 | 10302c73829 |
14 | 6b11d2a89d |
15 | 39b3d8191b |
hex | 20abb94c1b |
140320001051 has 2 divisors, whose sum is σ = 140320001052. Its totient is φ = 140320001050.
The previous prime is 140320001027. The next prime is 140320001111. The reversal of 140320001051 is 150100023041.
It is a weak prime.
It is an emirp because it is prime and its reverse (150100023041) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 140320001051 - 214 = 140319984667 is a prime.
It is a super-2 number, since 2×1403200010512 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (140320001011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70160000525 + 70160000526.
It is an arithmetic number, because the mean of its divisors is an integer number (70160000526).
Almost surely, 2140320001051 is an apocalyptic number.
140320001051 is a deficient number, since it is larger than the sum of its proper divisors (1).
140320001051 is an equidigital number, since it uses as much as digits as its factorization.
140320001051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 120, while the sum is 17.
Adding to 140320001051 its reverse (150100023041), we get a palindrome (290420024092).
The spelling of 140320001051 in words is "one hundred forty billion, three hundred twenty million, one thousand, fifty-one".
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