140320001011 has 2 divisors, whose sum is σ = 140320001012. Its totient is φ = 140320001010.

The previous prime is 140320000979. The next prime is 140320001023. The reversal of 140320001011 is 110100023041.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 140320001011 - 2⁵ = 140320000979 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 140320000982 and 140320001000.

It is not a weakly prime, because it can be changed into another prime (140320001051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70160000505 + 70160000506.

It is an arithmetic number, because the mean of its divisors is an integer number (70160000506).

Almost surely, 2^140320001011 is an apocalyptic number.

140320001011 is a deficient number, since it is larger than the sum of its proper divisors (1).

140320001011 is an equidigital number, since it uses as much as digits as its factorization.

140320001011 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24, while the sum is 13.

Adding to 140320001011 its reverse (110100023041), we get a palindrome (250420024052).

The spelling of 140320001011 in words is "one hundred forty billion, three hundred twenty million, one thousand, eleven".