Base | Representation |
---|---|
bin | 111111000111001111… |
… | …0010101101101111001 |
3 | 110221211121201000122112 |
4 | 1332032132111231321 |
5 | 4210033240212441 |
6 | 142132534302105 |
7 | 12535444401536 |
oct | 1761636255571 |
9 | 427747630575 |
10 | 135534304121 |
11 | 52530643797 |
12 | 223261b7935 |
13 | ca1c6395b8 |
14 | 67ba4d1d8d |
15 | 37d3b5c4eb |
hex | 1f8e795b79 |
135534304121 has 2 divisors, whose sum is σ = 135534304122. Its totient is φ = 135534304120.
The previous prime is 135534304117. The next prime is 135534304141. The reversal of 135534304121 is 121403435531.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 99310698496 + 36223605625 = 315136^2 + 190325^2 .
It is a cyclic number.
It is not a de Polignac number, because 135534304121 - 22 = 135534304117 is a prime.
It is a super-3 number, since 3×1355343041213 (a number of 34 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (135534304111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67767152060 + 67767152061.
It is an arithmetic number, because the mean of its divisors is an integer number (67767152061).
Almost surely, 2135534304121 is an apocalyptic number.
It is an amenable number.
135534304121 is a deficient number, since it is larger than the sum of its proper divisors (1).
135534304121 is an equidigital number, since it uses as much as digits as its factorization.
135534304121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 135534304121 its reverse (121403435531), we get a palindrome (256937739652).
The spelling of 135534304121 in words is "one hundred thirty-five billion, five hundred thirty-four million, three hundred four thousand, one hundred twenty-one".
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