Base | Representation |
---|---|
bin | 111111000111001111… |
… | …0010101101101110101 |
3 | 110221211121201000122101 |
4 | 1332032132111231311 |
5 | 4210033240212432 |
6 | 142132534302101 |
7 | 12535444401532 |
oct | 1761636255565 |
9 | 427747630571 |
10 | 135534304117 |
11 | 52530643793 |
12 | 223261b7931 |
13 | ca1c6395b4 |
14 | 67ba4d1d89 |
15 | 37d3b5c4e7 |
hex | 1f8e795b75 |
135534304117 has 2 divisors, whose sum is σ = 135534304118. Its totient is φ = 135534304116.
The previous prime is 135534304111. The next prime is 135534304121. The reversal of 135534304117 is 711403435531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 123295085956 + 12239218161 = 351134^2 + 110631^2 .
It is an emirp because it is prime and its reverse (711403435531) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 135534304117 - 211 = 135534302069 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135534304111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67767152058 + 67767152059.
It is an arithmetic number, because the mean of its divisors is an integer number (67767152059).
Almost surely, 2135534304117 is an apocalyptic number.
It is an amenable number.
135534304117 is a deficient number, since it is larger than the sum of its proper divisors (1).
135534304117 is an equidigital number, since it uses as much as digits as its factorization.
135534304117 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 75600, while the sum is 37.
Adding to 135534304117 its reverse (711403435531), we get a palindrome (846937739648).
The spelling of 135534304117 in words is "one hundred thirty-five billion, five hundred thirty-four million, three hundred four thousand, one hundred seventeen".
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