Base | Representation |
---|---|
bin | 111111000000101011… |
… | …0011010000110011001 |
3 | 110221021021101120100022 |
4 | 1332001112122012121 |
5 | 4204110403333423 |
6 | 142055031120225 |
7 | 12530132023553 |
oct | 1760126320631 |
9 | 427237346308 |
10 | 135314121113 |
11 | 52428325a66 |
12 | 22284513075 |
13 | c9b5b367b2 |
14 | 67991784d3 |
15 | 37be667dc8 |
hex | 1f8159a199 |
135314121113 has 2 divisors, whose sum is σ = 135314121114. Its totient is φ = 135314121112.
The previous prime is 135314121031. The next prime is 135314121121. The reversal of 135314121113 is 311121413531.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 131498341129 + 3815779984 = 362627^2 + 61772^2 .
It is a cyclic number.
It is not a de Polignac number, because 135314121113 - 28 = 135314120857 is a prime.
It is a super-2 number, since 2×1353141211132 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (135314121143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67657060556 + 67657060557.
It is an arithmetic number, because the mean of its divisors is an integer number (67657060557).
Almost surely, 2135314121113 is an apocalyptic number.
It is an amenable number.
135314121113 is a deficient number, since it is larger than the sum of its proper divisors (1).
135314121113 is an equidigital number, since it uses as much as digits as its factorization.
135314121113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1080, while the sum is 26.
Adding to 135314121113 its reverse (311121413531), we get a palindrome (446435534644).
The spelling of 135314121113 in words is "one hundred thirty-five billion, three hundred fourteen million, one hundred twenty-one thousand, one hundred thirteen".
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