Base | Representation |
---|---|
bin | 111111000000101011… |
… | …0011010000101000111 |
3 | 110221021021101120020021 |
4 | 1332001112122011013 |
5 | 4204110403333111 |
6 | 142055031120011 |
7 | 12530132023405 |
oct | 1760126320507 |
9 | 427237346207 |
10 | 135314121031 |
11 | 524283259a1 |
12 | 22284513007 |
13 | c9b5b3674b |
14 | 6799178475 |
15 | 37be667d71 |
hex | 1f8159a147 |
135314121031 has 2 divisors, whose sum is σ = 135314121032. Its totient is φ = 135314121030.
The previous prime is 135314121013. The next prime is 135314121113. The reversal of 135314121031 is 130121413531.
Together with previous prime (135314121013) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 135314121031 - 25 = 135314120999 is a prime.
It is a super-2 number, since 2×1353141210312 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 135314120987 and 135314121005.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (135314121931) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 67657060515 + 67657060516.
It is an arithmetic number, because the mean of its divisors is an integer number (67657060516).
Almost surely, 2135314121031 is an apocalyptic number.
135314121031 is a deficient number, since it is larger than the sum of its proper divisors (1).
135314121031 is an equidigital number, since it uses as much as digits as its factorization.
135314121031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1080, while the sum is 25.
Adding to 135314121031 its reverse (130121413531), we get a palindrome (265435534562).
The spelling of 135314121031 in words is "one hundred thirty-five billion, three hundred fourteen million, one hundred twenty-one thousand, thirty-one".
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