13311243204041 has 2 divisors, whose sum is σ = 13311243204042. Its totient is φ = 13311243204040.

The previous prime is 13311243204037. The next prime is 13311243204071. The reversal of 13311243204041 is 14040234211331.

13311243204041 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 7391248129225 + 5919995074816 = 2718685^2 + 2433104^2 .

It is a cyclic number.

It is not a de Polignac number, because 13311243204041 - 2² = 13311243204037 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13311243203995 and 13311243204013.

It is not a weakly prime, because it can be changed into another prime (13311243204071) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655621602020 + 6655621602021.

It is an arithmetic number, because the mean of its divisors is an integer number (6655621602021).

Almost surely, 2^{13311243204041} is an apocalyptic number.

It is an amenable number.

13311243204041 is a deficient number, since it is larger than the sum of its proper divisors (1).

13311243204041 is an equidigital number, since it uses as much as digits as its factorization.

13311243204041 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 13311243204041 its reverse (14040234211331), we get a palindrome (27351477415372).

The spelling of 13311243204041 in words is "thirteen trillion, three hundred eleven billion, two hundred forty-three million, two hundred four thousand, forty-one".