13311243204037 has 2 divisors, whose sum is σ = 13311243204038. Its totient is φ = 13311243204036.

The previous prime is 13311243203977. The next prime is 13311243204041. The reversal of 13311243204037 is 73040234211331.

13311243204037 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11418222195396 + 1893021008641 = 3379086^2 + 1375871^2 .

It is a cyclic number.

It is not a de Polignac number, because 13311243204037 - 2¹⁵ = 13311243171269 is a prime.

It is a super-2 number, since 2×13311243204037² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13311243203993 and 13311243204011.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13311243205037) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6655621602018 + 6655621602019.

It is an arithmetic number, because the mean of its divisors is an integer number (6655621602019).

Almost surely, 2^{13311243204037} is an apocalyptic number.

It is an amenable number.

13311243204037 is a deficient number, since it is larger than the sum of its proper divisors (1).

13311243204037 is an equidigital number, since it uses as much as digits as its factorization.

13311243204037 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 36288, while the sum is 34.

Adding to 13311243204037 its reverse (73040234211331), we get a palindrome (86351477415368).

The spelling of 13311243204037 in words is "thirteen trillion, three hundred eleven billion, two hundred forty-three million, two hundred four thousand, thirty-seven".