Base | Representation |
---|---|
bin | 1100000010010101000011… |
… | …1011111111011001110111 |
3 | 1201212011122211001210210220 |
4 | 3000211100323333121313 |
5 | 3213312020422024310 |
6 | 44051404025345423 |
7 | 2534064425103006 |
oct | 300452073773167 |
9 | 51764584053726 |
10 | 13234152142455 |
11 | 4242632964012 |
12 | 1598a4a938273 |
13 | 74cc8a6601ba |
14 | 33a771b8ac3d |
15 | 17e3b600e670 |
hex | c0950eff677 |
13234152142455 has 16 divisors (see below), whose sum is σ = 21193008280800. Its totient is φ = 7052092858368.
The previous prime is 13234152142439. The next prime is 13234152142483. The reversal of 13234152142455 is 55424125143231.
It is not a de Polignac number, because 13234152142455 - 24 = 13234152142439 is a prime.
It is a super-2 number, since 2×132341521424552 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 382583230 + ... + 382617819.
It is an arithmetic number, because the mean of its divisors is an integer number (1324563017550).
Almost surely, 213234152142455 is an apocalyptic number.
13234152142455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13234152142455 is a deficient number, since it is larger than the sum of its proper divisors (7958856138345).
13234152142455 is a wasteful number, since it uses less digits than its factorization.
13234152142455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 765202210.
The product of its digits is 576000, while the sum is 42.
Adding to 13234152142455 its reverse (55424125143231), we get a palindrome (68658277285686).
The spelling of 13234152142455 in words is "thirteen trillion, two hundred thirty-four billion, one hundred fifty-two million, one hundred forty-two thousand, four hundred fifty-five".
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