Base | Representation |
---|---|
bin | 1100000010010101000011… |
… | …1011111111011010010011 |
3 | 1201212011122211001210211221 |
4 | 3000211100323333122103 |
5 | 3213312020422024413 |
6 | 44051404025345511 |
7 | 2534064425103046 |
oct | 300452073773223 |
9 | 51764584053757 |
10 | 13234152142483 |
11 | 4242632964038 |
12 | 1598a4a938297 |
13 | 74cc8a66020c |
14 | 33a771b8ac5d |
15 | 17e3b600e68d |
hex | c0950eff693 |
13234152142483 has 2 divisors, whose sum is σ = 13234152142484. Its totient is φ = 13234152142482.
The previous prime is 13234152142439. The next prime is 13234152142489. The reversal of 13234152142483 is 38424125143231.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13234152142483 - 221 = 13234150045331 is a prime.
It is not a weakly prime, because it can be changed into another prime (13234152142489) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6617076071241 + 6617076071242.
It is an arithmetic number, because the mean of its divisors is an integer number (6617076071242).
Almost surely, 213234152142483 is an apocalyptic number.
13234152142483 is a deficient number, since it is larger than the sum of its proper divisors (1).
13234152142483 is an equidigital number, since it uses as much as digits as its factorization.
13234152142483 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 552960, while the sum is 43.
The spelling of 13234152142483 in words is "thirteen trillion, two hundred thirty-four billion, one hundred fifty-two million, one hundred forty-two thousand, four hundred eighty-three".
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